Question 881449
Perpendicular lines have slope that are negative reciprocals.
{{{m*3=-1}}}
{{{m=-1/3}}}
Use the point to solve for {{{b}}}.
{{{2=-(1/3)(2)+b}}}
{{{2=-2/3+b}}}
{{{b=6/3+2/3}}}
{{{b=8/3}}}
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{{{y=-(1/3)x+8/3}}}
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{{{drawing(300,300,-5,5,-5,5,grid(1),circle(2,2,0.2),graph(300,300,-5,5,-5,5,3x+4,-(1/3)x+8/3))}}}