Question 74230
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Factor Completely:
x^3 - 2x^2 - 4x - 8

My answer: 2(-2x^3 - x^2 - 2x - 2^2) 


This is factoring by grouping
                  x^3 - 2x^2 - 4x - 8
                 (x^3 - 4x) + (-2x^2 - 8)
                 x(x^2 - 4) + (-2)(x^2 - 4)
                 x(x^2 - 4) - 2(x^2 - 4)
Factor out the common factor
                 (x^2 - 4)(x - 2)