Question 881397
Mrs. Jones has three children. The youngest two children are twins. Find the ages of each of the three children if the difference between the oldest and youngest is three years and the sum of the ages of all children is 30.
**
let x=age of oldest child
x-3=age of twins
x+2(x-3)=30
x+2x-6=30
3x=24
x=8
x-3=5
age of oldest child=8
age of twins=5