Question 881395
{{{y=2x-4}}}
Perpendicular lines have slopes that are negative reciprocals.
{{{m*(2)=-1}}}
{{{m=-1/2}}}
So then,
{{{y-(-5)=-(1/2)(x-1)}}}
{{{2y+10=-x+1}}}
{{{highlight(2y+x=-9)}}}
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{{{drawing(300,300,-6,6,-9,3,grid(1),circle(1,-5,0.2),graph(300,300,-6,6,-9,3,2x-4,-(1/2)(x-1)-5))}}}