Question 881358
{{{f(x)=x^2-1/x^2}}}
{{{f(-x)=(-x)^2-1/(-x)^2}}}
{{{f(-x)=(-1)^2x^2-1/((-1)^2x^2)}}}
{{{f(-x)=x^2-1/x^2}}}
So,
{{{f(-x)=f(x)}}} so it is an even function.