Question 881287
find the area of the minor segment of a circle whose radius is 8 and has a central angle of 60. Use π =3.14 and round your answer to the nearest tenth. 
area of minor segment = area of sector - area of triangle  formed at center(1)
area of sector with center angle 60 degree =center angle x (pie r^2)/360
                                            =60 x3.14 x8 x8/360
                                             =3.14 x64/6 =33.4933
area of triage formed at center = r^2 sin(center angle) /2
                                =8^2 sin 60/2
                                =64 x sqrt3/4 =16 sqrt3=16 x1.7320=27.7128
 area of minor segment = area of sector - area of triangle  formed at center 
                       =33.4933-27.7128 =5.7805
Answer
Area of minor segment = 5.7805




















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