Question 881111
iregular pentagon 2 interior angles are 140 and 75 the other 3 are 2x, 3x, 3x+5 what is x and how do i work it out
-------------
The sum of the Int angles of a pentagon is 540 degs 180*(5 - 2)
-----
140 + 75 + 2x + 3x + 3x+5 = 540