Question 881178
Either {{{x^2+4x-3=2}}} Or {{{-x^2-4x+3=2}}}.


First case:
{{{x^2+4x-1=0}}}
{{{x=(-4+- sqr(20))/2}}}
{{{x=(-4+- 2*sqrt(5))/2}}}
{{{highlight(x=-2+- sqrt(5))}}}


Second case:
{{{-x^2-4x+3-2=0}}}
{{{-x^2-4x+1=0}}}
{{{x^2+4x-1=0}}}
{{{x=(-4+- sqrt(20))/2}}}
Same as the first case.