Question 74185
Solve by factoring:
{{{6x^2+10x+4 = 0}}} First, factor out a 2.
{{{2(3x^2+5x+2) = 0}}} Now factor the parentheses.
{{{(3x+2)(x+1) = 0}}} Now apply the zero product principle.
{{{3x+2 = 0}}}, so {{{3x = -2}}}...{{{x = -2/3}}}
{{{x+1 = 0}}}, so {{{x = -1}}}
The roots are:
{{{x = -2/3}}}
{{{x = -1}}}