Question 881102
x = first number
x + 1 = second number
x + 2 = third number


x + x + 1 + x + 2 = 333   {sum of the three consecutive numbers is 333}
3x + 3 = 333   {combined like terms}
3x = 330 {subtracted 3 from each side}
x = 110 {divided each side by 3}
x + 1 = 111   {substituted 110, in for x, into x + 1}
x + 2 = 112 {substituted 110, in for x, into x + 2}


sum of last two numbers 
= 111 + 112
= 223
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