Question 880972
{{{n}}}= the first (smaller) integer, so
{{{n+1}}}= the second (larger) integer;
{{{n+(n+1)=2n+1}}}= the sum of the two consecutive integers;
{{{3n}}}= three times the smaller integer;
{{{3n-4}}}= 4 less than three times the smaller integer.
The problem says that
{{{2n+1=3n-4}}}
and that is the equation that we need to solve.
{{{2n+1=3n-4}}}
{{{2n+1+4=3n}}}
{{{2n+5=3n}}}
{{{5=3n-2n}}}
{{{5=n}}}
So {{{n+1=5+1=highlight(6)}}} .
The two consecutive integers are 5 and 6, and the larger one is {{{highlight(6)}}} .