Question 73649
When you say {{{x^2=x*x}}} you're saying that you're multiplying 2 x's. When you go from {{{x^2}}} to {{{x^3}}} you're going to multiply x by {{{x^2}}} (ie {{{x*x^2=x^3}}}. To undo this, you divide. So if I go from x^3 to x^2, I'm saying {{{x^3/x=x*x*cross(x)/cross(x)}}} and I get x^2. So in a sense this applies {{{x^a/x^b=x^(a-b)}}}, with the example showing why it's true. So if I go from x^1 (which is x) to x^0 I would do this:

{{{x^0=x^(1-1)=x^1/x^1=x/x=1}}}and it will hold true for any x. Hope this makes sense.