Question 880812
Perpendicular lines have slopes that are negative reciprocals.
{{{5*m[p]=-1}}}
{{{m[p]=-1/5}}}
Use the point slope form,
{{{y-(-1)=-(1/5)(x-(-3))}}}}
{{{y+1=-(1/5)x-3/5}}}
{{{y=-(1/5)x-8/5}}}
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{{{drawing(300,300,-5,5,-5,5,grid(1),circle(-3,-1,0.2),graph(300,300,-5,5,-5,5,5x-12,-(1/5)x-8/5))}}}