Question 880768
{{{(27^(-2/3)^"")/(27^(-1/3)^"")}}}



{{{27^(-2/3-(-1/3))^""}}}



{{{27^(-2/3+1/3)^""}}}



{{{27^(-1/3)^""}}}



{{{1/(27^(1/3)^"")}}}



{{{1/(root(3,27))}}}



{{{1/(root(3,3^3))}}}



{{{1/3}}}



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So, {{{(27^(-2/3)^"")/(27^(-1/3)^"") = 1/3}}}