Question 880460
{{{x^3-y^3-2x+2y}}}



{{{(x^3-y^3)+(-2x+2y)}}}



{{{(x-y)(x^2+xy+y^2)+(-2x+2y)}}} Use the difference of cubes factoring rule to factor {{{x^3-y^3}}}



{{{(x-y)(x^2+xy+y^2)-2(x-y)}}}



{{{(x^2+xy+y^2)(x-y)-2(x-y)}}}



{{{(x^2+xy+y^2-2)(x-y)}}}



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So {{{x^3-y^3-2x+2y}}} factors to {{{(x^2+xy+y^2-2)(x-y)}}}