Question 880406
f(x) = {{{x^2-8/x-3 }}}
f(2) Plug and Play
f(2)= 4 -4 - 3 = -3
(2, -3) a point on the graph of f
0r...
IF
f(x) = {{{x^2-8/(x-3) }}}
f(2) = 4+8 = 12
(2, 12) a point on the graph of f
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