Question 74142
y=-4x^2+8x-1 in vertex form
Vertex form is y=(x-h)^2+k, where (h,k)=vertex
y=-4(x^2-2x+___)+4(__)-1
y=-4(x^2-2x+(-2/2)^2)+4(-2/2)^2-1
y=-4(x^2-2x+(-1)^2)+4(-1)^2-1
y=-4(x^2-2x+1)+4(1)-1
y=-4(x-1)^2+3
The vertex is now easily determined to be: (1,3)
Happy Calculating!!!!