Question 880336
Let me abbreviate the first few steps through description:


Multiply the right-hand side by {{{(10^x)/(10^x)}}}, and simplify.
Multiply left and right sides by {{{10^(2x)+1}}}.
After some use of Distributive Property and use of additive inverse property, you should obtain:
{{{10^(2x)=(y+1)/(1-y)}}}
Then taking common logs of both sides, obtain
{{{highlight(x=(1/2)log(10,((y+1)/(1-y))))}}}
or
to make that easier to read when rendered, just understand COMMON LOGS,
{{{highlight(x=(1/2)log(((y+1)/(1-y))))}}}