Question 880266
Graph the line {{{x + 3y = 6}}}. This line goes through (0,2) and (6,0). Let me know if you need me to walk you through this portion.


This line is a solid line.


Now plug in the test point (0,0)


{{{x + 3y <= 6}}}
{{{0 + 3(0) <= 6}}}
{{{0 <= 6}}} 


The last inequality is true. So (0,0) is in the solution set. So you shade below the solid line.


This is what the graph will look like


{{{ drawing( 500, 500, -10, 10, -10, 10,

line(18,-4,-12,6),
graph( 500, 500, -10, 10, -10, 10, 0, y<(6-x)/3-.05)
graph( 500, 500, -10, 10, -10, 10, 50)

) 
}}}


Shaded region in green with the solid black boundary line.