Question 880272
First attempt to understand your equation is that the base is 3.  If this is the case, then {{{log(3,(x+6)(x-6)/x)=2}}}.
{{{log(3,(x^2-36)/x)=2}}}

{{{3^2=(x^2-36)/x}}}
{{{9x=x^2-36}}}
{{{x^2-9x-36=0}}}

{{{x=(9+- sqrt(81+4*36))/2}}}
{{{x=(9+- sqrt(225))/2}}}
{{{x=(9+- sqrt(9*25))/2}}}
{{{x=(9+- 15)/2}}}


{{{highlight(x=-3)}}} or {{{highlight(x=12)}}}.