Question 880156
The difference in their ages never changes
I can call this difference {{{ c }}}
Let {{{ x }}} = the age of the younger person
Let {{{ y }}} = the age of the older person
{{{ y = x + c }}}
I want the age of the older person to be {{{ 3x }}}, so
{{{ 3x = x + c }}}
{{{ c = 2x }}}
{{{ x = c/2 }}}
------------
{{{ y = c/2 + c }}}
{{{ y = (3/2)*c }}}
This is telling me that when the older person is 3/2
times the difference in their ages, then the older
person will be 3 times the age of the younger
----------------
To test this, I'll say
Older person = 42
Younger person = 9
{{{ c= 42 - 9 }}}
{{{ c = 33 }}}
and
{{{ (3/2)*33 = 49.5 }}}
Older  = {{{ 49.5 }}}
Younger = {{{ 49.5 - 33 }}}
Younger = {{{ 16.5 }}}
-------------------
check:
{{{ 49.5 = 3*16.5 }}}
{{{ 49.5 = 49.5 }}}
It works