Question 880149
Replace h(x) with y. Then swap x and y. Then solve for y.



{{{h(x) = 4(x - 7)^3}}}



{{{y = 4(x - 7)^3}}}



{{{x = 4(y - 7)^3}}}



{{{x/4 = (y - 7)^3}}}



{{{(y - 7)^3 = x/4}}}



{{{y - 7 = root(3,x/4)}}}



{{{y = root(3,x/4)+7}}}



The inverse is {{{h^(-1)(x) = root(3,x/4)+7}}}