Question 880116
Blaise rode hi bike to him friend elroy's house, which was 15 miles away.
 After he had been riding for half an hour, he got a flat tire.
 He walked his bike the rest of the way.
 The total trip took him 3 hours.
 if his walking rate was one-fourth as fast as his riding rate, how fast did he ride?
:
let w = his walking speed
then
4w = his riding speed
:
From the information given we know that he rode for .5 hrs, therefore:
He walked 2.5 hrs
:
Write a distance equation; dist = time * speed
walk dist + ride dist = 15 mi
2.5w + .5(4w) = 15
2.5w + 2w = 15
4.5w = 15
w = 15/4.5
w = 3{{{1/3}}} mph his walking speed
then
3.333 * 4 = 13{{{1/3}}} mph, his riding speed
:
:
Check this out, find how far he biked and how far he walked
.5 * 13.333 = 6.67 mi
2.5 * 3.333 = 8.33 mi
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total dist: 15.00 mi