Question 74130
please help me to solve this: 1/81=27^(x-2)
{{{81^(-1)=27^(x-2)}}}
{{{(3^4)^(-1)=(3^3)^(x-2)}}}
{{{3^(-4)=3^(3(x-2))}}}
Once the bases are the same, equate their exponents.
-4=3(x-2)
-4=3x-6
-4+6=3x-6+6
2=3x
2/3=3x/3
x=2/3
Happy Calculating!!!!