Question 879996
{{{sin^2(theta)+cos^2(theta)=1}}}
{{{sin^2(theta)+9/25=1}}}
{{{sin^2(theta)=25/25-9/25}}}
{{{sin^2(theta)=16/25}}}
{{{sin(theta)=0 +- 4/5}}}
So then,
{{{tan(theta)=sin(theta)/cos(theta)=(4/5)/(3/5)=4/3}}} or {{{tan(theta)=-4/3}}}