Question 879898
I think you mean sqrt(5-x) instead of (sqrt(5)-x).
{{{sqrt(5-x)+2=x-1}}}
{{{sqrt(5-x)=x-3}}}
{{{5-x=(x-3)^2}}}
{{{5-x=x^2-6x+9}}}
{{{x^2-5x+4=0}}}
{{{(x-1)(x-4)=0}}}
Two solutions:
{{{x-1=0}}}
{{{x=1}}}
and
{{{x-4=0}}}
{{{x=4}}}
Verify the solution by using the original equation.
{{{sqrt(5-1)+2=1-1}}}
{{{sqrt(4)+2=0}}}
{{{2+2=0}}}
No, not a solution.
{{{sqrt(5-4)+2=4-1}}}
{{{sqrt(1)+2=3}}}
{{{3=3}}}
True, {{{x=4}}} is a solution.