<PRE><B>Question 879925</B>
The sum of three numbers is 105. The third number is 11 less than 10 times the second number. Twice the first number is 7 more than 3 times the second number. Find each number.
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let x=2nd number
let y=1st number
10x-11=3rd number
2y=3x+7
3x-2y=-7
..
x+y+10x-11=105
11x+y=116
3x-2y=-7
..
22x+2y=232 (mult. by 2)
  3x-2y=-7
add
25x=225
x=9
10x-11=79
2y=3x+7=27+7=34
y=17
2nd number=9
1st number=17
3rd number=79
Check: 9+17+79=105
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