Question 879918
{{{x^2+3x>-7-5x}}} 
{{{x^2+3x+5x+7>0}}}
{{{x^2+8x+7>0}}}, factorable?  Yes.
{{{(x+1)(x+7)>0}}}


The critical values are at -1 and -7.


Test each of the three intervals, {{{-oo<x<-7}}};
{{{-7<x<-1}}}; and {{{-1<x<oo}}}.