Question 879705
{{{2^(x+1)=2^x*2^1=2*2^x}}}
{{{2^(x-1)=2^x*2^(-1)=(1/2)2^x}}}
So then,
{{{2^(x+1)+2^(x-1)=150}}}
{{{2*2^x+(1/2)*2^x=160}}}
{{{(2+1/2)*2^(x)=160}}}
{{{(5/2)2^(x)=160}}}
{{{2^x=320/5}}}
{{{2^x=84}}}
{{{x=log((84))/log((2))}}}