Question 879542
Your part A and part B are a little difficult to follow but maybe this will help:


{{{5x-5y=10}}} can be simplified, dividing left and right members by 5, to give {{{x-y=2}}}.


Your system is then equivalent to
{{{x-y=2}}} and {{{3x-2y=2}}}.
You can solve this system with the Elimination Method.  The simplest way to start this is to try to match the coefficient on y in the second equation of the system.  The way to do this is multiply the left and right members of the first equation by 2, yielding the system:  {{{2x-2y=4}}} AND {{{3x-2y=2}}}.
Now, simply subtract one equation from the other equation:
{{{2x-2y-(3x-2y)=4-2}}}
{{{2x-2y-3x+2y=2}}}
{{{-x+0=2}}}
{{{highlight(x=-2)}}}
-
Now, you might prefer not to again use elimination of x in order to find y; but instead to simply substitute for x=-2 in either equation of the system and solve for y.



... y=-4.