Question 879452
of the two numbers,
a & b
4 times the first is equal to 6 times the other
4a = 6b
or
4a - 6b = 0
: 
and the sum of 3 times the first and 6 times the second is 105.
3a + 6b = 105
4a - 6b = 0
--------------------adding the two equations eliminates b, finda
7a = 105
a = 105/7
a = 15  is the first number

;
:
Check this, 4(15) = 6b
60 = 6b
b = 60/6
b = 10
3(15) + 6(10) = 105
45 + 60 = 105