Question 74099
{{{f(x) = (x-1)/(x+1)}}} Is this correct?
{{{f(1/x) = ((1/x)-1)/((1/x)+1)}}} Simplifying this, we get:
{{{f(1/x) = (1-x)/(1+x)}}} = {{{-(x-1)/(x+1)}}}, so...
{{{f(x)-f(1/x) = ((x-1)/(x+1))-(-(x-1)/(x+1))}}}={{{2((x-1)/(x+1))}}}