Question 879559
Solve the equation using the quadratic formula. 
1. 3x^2+12x+2=0
a=3, b=12, c=2
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-12 +- sqrt(12^2-4*3*2 ))/(2*3) }}}
{{{x = (-12 +- sqrt(144-24))/(6) }}}
{{{x = (-12 +- sqrt(120))/(6) }}}
{{{x = (-12 +- sqrt(4*30))/(6) }}}
x=(-12±2√30)/6=-2±√30/3