Question 74080
Given:
{{{f(x)=x^2-7x +10}}}

Find: (a) f(0), (b) f(5), and (c) f(-2)
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All this problem require you to do is assign values to x and solve for the given function.
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In (a) f(0) means go to the given function and substitute 0 for every x you find. When you
do that the function is:
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{{{f(0)=0^2-7*0 +10}}} and this simplifies it to {{{f(0) = 0 + 0 +10}}} which reduces to:
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{{{f(0) = +10}}}
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In (b) f(5) means go to the given function and replace all the x's in it with 5.  When you do
it becomes: {{{f(5) = 5^2 - 7*5 + 10 = 25 - 35 + 10}}} which reduces to:
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{{{f(0) = 25 -35 + 10 = 0}}} so that {{{f(5) = 0}}}
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In (c) {{{f(-2) = (-2)^2 -7*(-2) + 10}}} which becomes {{{f(-2)= 4 + 14 +10}}} and this
simplifies to {{{f(-2) = 28}}}
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Hope this helps you to understand the problem.