Question 879509
{{{log(25,(49))=y}}}
{{{25^y=49}}}
{{{(5^2)^y=7^2}}}
{{{sqrt(5^(2y))=sqrt(7^2)}}}
{{{5^(y)=7}}}
{{{log(5,(7))=y}}}
They both equal {{{y}}} so they equal each other.