Question 879462
First graph the line {{{6x+3y=24}}} or {{{2x+y=8}}}
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{{{graph(300,300,-10,10,-10,10,(24-6x)/3)}}}
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Now choose a point not on the line and check it in the inequality.
(0,0) is convenient.
{{{6(0)+3(0)>24}}}
{{{0>24}}}
False, so (0,0) is not in the solution region. 
Shade the region not containing (0,0).
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{{{graph(300,300,-10,10,-10,10,6x + 3y > 24)}}}