Question 879489
 x^2 + 10x + 38 = (x+5)^2 + 13  Nice Work
a) minimum value of x^2 + 10x + 38 is  13 when x = -5 
b) 22 ≤ (x+5)^2 + 13
   9  ≤ (x+5)^2
  ±3 ≤ x+5
 -8 ≤ x ≤ -2
{{{drawing(300,300,  -20,5,-50,50,  grid(1),
circle(-5, 13,0.2),
graph( 300, 300,-20,5,-50,50,0, x^2 + 10x + 38))}}}