Question 879438
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All you have done is attempt to put the original equation into slope-intercept form.  Correctly done, you would have simply had another equation for the same line.  Re-do the part you have done paying particular care with signs when solving *[tex \Large 3x\ +\ 4y\ =\ 12] for *[tex \Large y] to get the correct slope intercept equation for your given line.  Once you have done that, replace the constant term with a variable such a *[tex \Large b], and substitute the coordinates of the given point, that is 2 for *[tex \Large x] and -5 for *[tex \Large y].  That leaves you with a single variable equation in *[tex \Large b].  Solve for *[tex \Large b] and substitute back into your slope-intercept form equation to get the equation of the desired parallel.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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