<PRE><B>Question 879442</B>
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Use your calculator to find *[tex \LARGE \arccos\left(\frac{12}{13}\right)]


This might be *[tex \LARGE \cos^{-1}] instead of *[tex \LARGE \arccos] on some calculators.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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