Question 879072
Plug it into the inequality.
{{{y<=(3/2)x+3}}}
{{{0<=(3/2)5+3}}}
{{{0<=15/2+6/2}}}
{{{0<=21/2}}}
If it's true, then (5,0) is a solution, if it's false then it's not a solution.
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{{{-4<=(3/2)(0)+3}}}
{{{-4<=3}}}
Again, same as before.