Question 878779
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Hi, Previously Posted
x-3=-2((y+4)^2)=3 ??? too many = signs
Anyhow: 4p = -1/2, p = -1/8  Parabola Opens left(-2 < 0) along line of symmetry: y = -4
Need to know the Vertex point..going to guess V(3,-4) &#8658; focus is F(2 7/8, -4)
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the vertex form of a Parabola opening right(a>0) or left(a<0), {{{x=a(y-k)^2 +h}}}
 where(h,k) is the vertex and  y = k  is the Line of Symmetry
The standard form is {{{(y -k)^2 = 4p(x -h)}}}, 0r a = 1/4p, where  the focus is (h +p,k )  With Directrix x = (k-p)