Question 878649
Solve 
a) log( base 4) (x+3) + log( base 4) (x-3) = 2
{{{log(4,(x+3))+log(4,(x-3))=2}}}
{{{log(4,(x+3)(x-3))=2}}}
{{{log(4,(x^2-9))=2}}}
x^2-9=4^2=16
x^2=25
x=±5