Question 878319
 Jim takes 1/4 of all the bars, and ken and len each take 1/3 of all the bars. Max gets the remaining 4 bars.
 How many bars were there in the bag originally?
 How many bars did jim, ken, and len each get?:
;
Let x = total no. of bars
x = {{{1/4}}}x + {{{2/3}}}x + 4
multiply by 12, cancel the denominators
12x = 3x + 8x + 12(4)
12x = 11x + 48
12x - 11x = 48
12x - 9x = 8x
x = 48 bars originally
then
{{{1/4}}} * 48 = 12 for jim
{{{1/3}}} * 48 = 16 for len & ken
:
:
Check 12 + 16 + 16 + 4 = 48