Question 878404
I'm assuming the following:
68 is the hypotenuse
8 is leg b
If so, use the formula {{{a^2}}}+{{{b^2}}}={{{c^2}}} where a & b are the sides of a right triangle and c is the hypotenuse.
{{{a^2}}}+8 = 68
Subtract 8 from each side
{{{a^2}}}=60
Take the square root of each side
a = 7.746
.
HOWEVER... If, as I suspect, leg b is 8 long (rather than 8 being the square), the equation becomes:
{{{a^2}}}+{{{8^2}}} = 68
{{{a^2}}}+ 64 = 68
Subtract 64 from each side
{{{a^2}}}=4
Take the square root of each side
a = 2