Question 878465
{{{x^2-11x+30.25}}} is in the form {{{ax^2+bx+c}}} where {{{a = 1}}}, {{{b = -11}}}, {{{c = 30.25}}}  

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Use the quadratic formula to solve for x


{{{x = (-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x = (-(-11)+-sqrt((-11)^2-4(1)(30.25)))/(2(1))}}} Plug in {{{a = 1}}}, {{{b = -11}}}, {{{c = 30.25}}}  


{{{x = (11+-sqrt(121-121))/(2)}}}


{{{x = (11+-sqrt(0))/2}}}


{{{x = (11+sqrt(0))/2}}} or {{{x = (11-sqrt(0))/2}}}


{{{x = (11+0)/2}}} or {{{x = (11-0)/2}}}


{{{x = 11/2}}}



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The only solution is {{{x = 11/2}}}