Question 877918
A. Solve log4 (3x-7)<2
3x-7<16
3x<23
x<23/3
.. 
B.Solve log9 (3x-7)>= log9 (2x+9)
3x-7&#8805;2x+9
x&#8805;16
.. 
C. Evaluate (Log4 12^3) (log12 4^3)
{{{log(4,(12^3))*log(12,(4^3))}}}
{{{3log(4,(12))*3log(12,(4))}}}
convert to base 4
{{{3log(4,(12))*3log(4,(4))/log(4,(12))}}}
{{{3log(4,(12))*3/log(4,(12))}}}=3*3=9