Question 878378
{{{sqrt(5-x)<x+1}}}
{{{5-x<x^2+2x+1}}}
{{{x^2+3x-4>0}}}
{{{(x+4)(x-1)>0}}}
The solution for this is {{{x<-4}}} and {{{x>1}}}.
However the negative solutions do not solve the equation, they only do so when the two sides are squared so only {{{x>1}}} is accepted as a solution.
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In addition, we have an additional constraint with the square root function.
{{{5-x>=0}}}
{{{x<=5}}}
So putting those together, the solution region is,
{{{1<x<=5}}}