Question 878332
{{{tan(theta)=(1-cos(2*theta))/sin(2*theta)}}}
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{{{cos(2*theta)=cos^2(theta)-sin^2(theta)}}}
{{{1-cos(2*theta)=1-cos^2(theta)+sin^2(theta)}}}
{{{1-cos(2*theta)=sin^2(theta)+sin^2(theta)}}}
{{{1-cos(2*theta)=2sin^2(theta)}}}
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{{{sin(2*theta)=2cos(theta)sin(theta)}}}
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{{{tan(theta)=(2sin^2(theta))/(2cos(theta)sin(theta))}}}
{{{tan(theta)=sin(theta)/cos(theta)}}}
{{{tan(theta)=tan(theta)}}}
True.