Question 878337
Use parentheses to make it more readable. 
{{{1/(m-1)=3/m-2/(m+2)}}}
{{{(m(m+2))/(m(m-1)(m+2))=3((m-1)(m+2))/(m(m-1)(m-2))-2(m(m-1))/(m(m-1)(m+2))}}}
{{{(m(m+2)-3(m-1)(m+2)+2m(m-1))/(m(m-1)(m+2))=0}}}
{{{(m^2+2m-3(m^2+m-2)+2m^2-2m)/(m(m-1)(m+2))=0}}}
{{{(m^2+2m-3m^2-3m+6+2m^2-2m)/(m(m-1)(m+2))=0}}}
{{{(6-3m)/(m(m-1)(m+2))=0}}}
{{{3m=6}}}
{{{highlight(m=2)}}}
Verifying,
{{{1/(2-1)=3/2-2/(2+2)}}}
{{{1=3/2-1/2}}}
{{{1=2/2}}}
{{{1=1}}}
True, good solution.