Question 878222
population: m = 24, sd = 4
Sample of 49
P(x < 15) = P(z< -9/(4/sqrt(49) = P(z < -9/.5714) = P(z < -15.75)basically zero chance
P(x > 26) = P(z > 2/.5714) = P(z > 3.50) = .0003
As You can see below, 
z = 3.50 is way to the right and z = -15.75 is 'off the charts' way to the left.
Below:  z = 0, z = ± 1, z= ±2 , z= ±3 are plotted along the Standard Normal Curve  
Note: z = 0 (x value: the mean) 50% of the area under the curve is to the left and 50% to the right
{{{drawing(400,200,-5,5,-.5,1.5, graph(400,200,-5,5,-.5,1.5, exp(-x^2/2)), green(line(1,0,1,exp(-1^2/2)),line(-1,0,-1,exp(-1^2/2))),green(line(2,0,2,exp(-2^2/2)),line(-2,0,-2,exp(-2^2/2))),green(line(3,0,3,exp(-3^2/2)),line(-3,0,-3,exp(-3^2/2))),green(line( 0,0, 0,exp(0^2/2))),locate(4.8,-.01,z),locate(4.8,.2,z))}}}